576=-16t^2+128t+320

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Solution for 576=-16t^2+128t+320 equation: 



576=-16t^2+128t+320

We move all terms to the left:

576-(-16t^2+128t+320)=0

We get rid of parentheses

16t^2-128t-320+576=0

We add all the numbers together, and all the variables

16t^2-128t+256=0

a = 16; b = -128; c = +256;
Δ = b2-4ac
Δ = -1282-4·16·256
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{128}{32}=4$

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